QUANT QUIZ ON DI
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Directions (1-5): Study the following graph carefully and answer the questions given below.
The following graph gives the profit percentage of three companies in different years.
Profit = Income – expenditure
Profit % = [ {Income – expenditure} / expenditure] * 100
1.What is the ratio of profit incurred by companies A to profit incurred by companies B in 2008?
(1) 10 : 9 (2) 9 : 10
(3) 30 :29 (4) 29 : 30
(5) cannot be determined
2.If the income of company B and C was equal in 2009, then what was the ratio of their expenditures?
(1) 12 : 13 (2) 13 : 12
(3) 3 : 2 (4) 2 : 3
(5) None of these
3.Which company earned the minimum percentage profit for maximum number of years during the given period?
(1) A (2) B
(3) C (4) Both B and C
(5) Both A and C
4.If company A and C has equal profit in 2010, then Income earned by company C is (approx) what percent of the expenditures incurred by company A?
(1) 230 (2) 260
(3) 45 (4) 180
(5) 80
5.If the expenditure of company A keep on increasing every year, then in which year it has maximum income?
(1) 2007 (2) 2008
(3) 2009 (4) 2010
(5) None of these
Directions—(6–10) Study the graphs carefully to answer the following question:
Total number of children in 6 different schools and the percentage of girls in them.
6.What is the percentage of boys in schools R and U together? (Rounded off to two digits after decimal)
(1) 78.55% (2) 72.45%
(3) 76.28% (4) 75.83%
(5) None of these
7.What is the total number of boys in school T?
(1) 500 (2) 600
(3) 750 (4) 850
(5) None of these
8.The total number of students in school R is approximately what percent of the total number of students in school S?
(1) 89% (2) 75%
(3) 78% (4) 82%
(5) 94%
9.What is the average number of boys in schools P and Q together?
(1) 1425 (2) 1575
(3) 1450 (4) 1625
(5) None of these
10. What is the respective ratio of the number of girls in school P to the number of girls in school Q?
(1) 27:20 (2) 17:21
(3) 20:27 (4) 21:17
(5) None of these
ANSWERS:
1.
1.
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(5)
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2.
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(1)
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3.
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(4)
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4.
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(1)
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5.
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(4)
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6.
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(4)
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7.
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(3)
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8.
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(1)
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9.
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(2)
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10.
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(3)
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Solutions (1-5):
1.Since the value of expenditure is not given for the two companies, we cannot find the ratio of their profits
2.Let the expenditures of company B and C were x and y respectively in the year 2009.
Now, Income = [ {profit% /100} +1]* expenditure
So Income of B= Income of C
1.3x = 1.2 y
x : y = 12 : 13
3.In 2007, Company B earned minimum percentage profit.
In 2008, Company C earned minimum percentage profit.
In 2009, Company C earned minimum percentage profit.
In 2010, Company B earned minimum percentage profit.
Hence both companies B and C earned the minimum percentage profit two (maximum) times.
4.Let the expenditures of company A and C were x and y respectively in the year 2010. Then
Profit of A= 60% of x
& Profit of A= 35% of y
So, 0.6 x = 0.35y
x :y = 7 : 12
let x = 7p & y = 12p
Expenditure of company A = 7p
Expenditure of company C = 12p
Income = [ {profit% /100} +1]* expenditure
Income of company C =
Required percentage = 16.2p/7p *100 = 230% (approx)
5.Since the expenditure kept on increasing, company A has maximum expenditure in 2010. Also the profit % is maximum for 2010, so the income will also be maximum for 2010.
Solutions (6-10):
6.Required percentage =[ {72.5% of 2000 + 82.5% of 1000} / 3000 ] *100 = 75.83%
7.Total boys = 60% of 1250 = 750
8.Required Percentage = [ 2000 / 2250] *100=88.88% 0r 89% (approx).
9.Required Average = [60% of 2500 + 55% of 3000] /2 = 1575
10. 1000:1350=20:27
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