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Daily GK Updates - 14th Oct 2014

Tuesday, October 14, 2014 / No Comments


Welcome to ourindiajobs.com. Daily GK Updates  will helps you to crack your online bank exams. Success comes from confidence. Go ahead with confidence, win the race and achieve your target. All the best for test.

1.    Khaled Bahah new PM of Yemen

i. In Yemen, President Mansour Hadi has named country’s envoy to UN, Khaled Bahah as the next Prime Minister. He was among the three names proposed by the Houthi rebels to end the political standoff in the country.
ii. The rebel group has welcomed the move and said his appointment will help the country overcome the difficulties it is going through. He has earlier served as Yemen’s oil minister before being named as Yemen’s envoy to the United Nations.


2.    PM announces interim assistance of Rs 1000 crore for AP

i. Prime Minister Narendra Modi on Tuesday announced an interim assistance of Rs 1,000 crore for Andhra Pradesh to take up immediate relief work in the aftermath of the devastation caused by Cyclone 'Hudhud'.
ii. He also announced an ex-gratia of Rs two lakh to the next of kin of those killed in the cyclone and Rs 50,000 to the injured.
Iii. The Prime Minister said the Meteorological Department had correctly forecast from October six itself the different aspects of the cyclone like its velocity, direction and time, leveraging the power of technology.


3.    Global Hunger Index Report 2014 released: India Ranked at 55th Position

i. The 2014 Global Hunger Index (GHI) was released by the International Food Policy Research Institute (IFPRI), Welthungerhilfe and Concern Worldwide.
ii. It revealed that two billion people were suffering from hidden hunger even though the levels of hunger in many developing countries decreased.
iii. The 2014 GHI was calculated for 120 developing countries and countries in transition, 55 of which have a serious or worse hunger situation.
iv. India improved its position in the Global Hunger Index in 2014 as it climbed to 55th position among  76 emerging economies from 63rd position in 2013. Though, it is still trailing behind countries like Thailand, China, Ghana, Iraq, Sri Lanka and Nepal.


4.    Ajay Jayaram won Dutch Open Grand Prix badminton tournament

i. Indian shuttler, Ajay Jayaram won the 50000 dollar Dutch Open Grand Prix badminton tournament on 12 October 2014.
ii. In the title clash played at the Topsportcentrum Almere in Netherlands, Jayaram defeated Indonesia’s Ihsan Maulana Mustofa 10-11, 11-6, 11-7, 1-11, 11-9.
iii. This was maiden GP title for Jayaram and with this win, he also became the first Indian to win badminton Grand Prix tournament under the new 11x5 scoring system.


5.    Mary Kom voted as India's Most Valuable Player in Asian Games 2014

i. Olympic bronze medalist MC Mary Kom on 13 October 2014 was chosen as the Most Valuable Player (MVP) of India’s Incheon Asian Games campaign at a felicitation of the medal winners by contingent sponsors, Samsung India.
ii. Kom, the first Indian woman boxer to win a gold medal in Asian Games was named as the MVP in a poll conducted by Samsung.
iii. After topping the list, the gold medalist in the 2014 Incheon Games in flyweight (-51kg) class, Mary Kom received 10 lakh rupees.


6.    Lyricist Sameer honoured with Kishore Kumar Award for 2012-13

i. Noted lyricist Sameer was honoured with the National Kishore Kumar Award for 2012-13. He was awarded during a function at the legendary singer's birth place Khandwa in Madhya Pradesh.
ii. The award was handed over to Sameer by Madhya Pradesh Food and Civil Supplies Minister Kunwar Vijay Shah.


7.    JP Morgan cut India 2014-15 growth forecast to 5.1 percent from 5.3 percent

i. JP Morgan on 10 October 2014 cut its India GDP growth projection for 2014-15 to 5.1 percent from 5.3 percent.
ii. JP Morgan cited that the industrial output of India in August 2014 rose to 0.4 percent compared to the estimation it was very low.
iii. The Reserve Bank of India projects GDP to grow at around 5.5 percent in the current fiscal year ending March 2015.

Reasoning Quiz - IX

Monday, October 13, 2014 / No Comments


Welcome to ourindiajobs.com online test on reasoning. Reasoning tests will helps you to crack your online bank exams. This material on reasoning will be covered with all topics. Little bit of concentration and hard work may do this online test on reasoning. Practice more tests on reasoning it will helps you to manage time. Success comes from confidence. Go ahead with confidence, win the race and achieve your target. All the best for test.



Directions (1-5): Study the following information to answer the questions given below it:

I.  A, B, C, D, E, F and G are seven members of a family.
II. There are two Doctors, two Teachers, two Professors and one Lawyer.
III. No lady is either Teacher or Lawyer.
IV. Teacher's wife is a Professor and Lawyer's wife is also a Professor.
V. C is the daughter-in-law of F and mother of E.
VI. B, a Doctor, is son of G, and E, who is not a Professor, is the daughter of Lawyer.
VII. A's husband is a Teacher and A is the mother-in-law of C and grandmother of B.
VIII. F is the grandfather of B and D.


1. All the family members belong to how many generations?
(1) Four
(2) Two
(3) Either two or three
(4) Cannot be determined
(5) None of these

2. Which of the following is one of the married couple?
(1) GC
(2) FC
(3) GA
(4) Cannot be determined
(5) None of these

3. How is D related to A?
(1) Granddaughter
(2) Son
(3) Grandson
(4) Cannot be determined
(5) None of these

4. What is C to D?
(1) Daughter-in-law
(2) Son-in-law
(3) Daughter
(4) Cannot be determined
(5) None of These

5. How many female members are there in the family?
(1) Two
(2) Three
(3) Four
(4) Cannot be determined
(5) None of These

Directions (6-10): In the questions given below, certain symbols are used with the following meanings:
P # Q means P is neither equal to nor smaller than Q.
P % Q means P is not smaller than Q
P $ Q means P is neither greater nor smaller than Q.
P & Q means P is neither greater than nor equal to Q
P @ Q means P is not greater than Q.
Now in each of the following questions, assuming the given statements to be true, find which of the two conclusions I and ii given below them is / are definitely true. Give answer
(1) If only conclusion I is true
(2) If only conclusion II is true.
(3) If either conclusion I or II is true.
(4) If neither conclusion I and II are true.
(5) If both conclusions I and II are true.

6. Statements:  T % U, Q @ R, R & U
Conclusions:
I. T # Q
II. R @ T

7. Statements:  Q & T, W # X, Q % X
Conclusions:
I. W $ Q
II. X & T

8. Statements:  Y $ Z, B # A, Y & A
Conclusions:
I. A # Z
II. Y & B

9. Statements:  K # L, N @ O, L $ O
Conclusions:
I. L # N
II. N $ L

10. Statements: P % Q, Q $ R, R # S, S & T
Conclusions:
I. R # P
II. R $ P


ANSWERS


1. 5
2. 1
3. 3
4. 5
5. 2
6. 1
7. 2
8. 5
9. 3
10. 4

Quantitative Aptitude Quiz - XII

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Directions (Q. 1-5): What should come in place of question mark (?) in the following number series?

1. 5, 41, 321, 1921, 7681, 15361, ?
1) 21381
2) 23710
3) 22173
4) 23121
5) 1


2. 1, 3, 7, 13, 22, 34, 51, 71, 96, 124, ?
1) 137
2) 147
3) 157
4) 167
5) None of these

3. 664, 334, 85.5, 16.25, 4.03125, ?
1) 2.73012
2) 3.17203
3) 2.403125
4) 3.220175
5) None of these

4. 33, 110, 453, 2282, 13711, ?
1) 95673
2) 96747
3) 96312
4) 951321
5) 96000

5. 0.8, 3.8, 12.6, 44.8, 188.2, ?
1) 758.6
2) 868.8
3) 952.00
4) 1012.2
5) 1112.2


Directions (Q. 6-10): In the following questions two  equation numbered I and II are given. You have solve the equation and give answer if-
1.  x > y
2.  x >  y
3.  x < y
4.  x < y
5.  x = y or the relationship cannot be established.


6.    
I. 20x2 - 31x + 12 = 0          
II. 20y2 - y  - 12 = 0

7.    
I. 3x2 - 47x + 184 = 0          
II. 2y2 - 23y + 66 = 0

8.    
I. 30x - 49√x + 20 = 0          
II. 42y - 5√y - 25 = 0

9.    
I.  x2 - 10√3x + 63 = 0            
II. y2 - √2y - 24 = 0


10.    
I. x2 - 14x + 48 = 0                            
II. y2 - y - 30 = 0



ANSWERS:


1.    5;    The series is:
                5 × 10 – 9 = 41
                41 × 8 – 7 = 321
                321 × 6 – 5 = 1921
                1921 × 4 – 3 = 7680
                7681 × 2 – 1 = 15361
                15361 × 0 – (–1) = 1

2.    3;    The series is:
                1 + 1 + 1 = 3
                3 + 2 + 2 = 7
                7 + 3 + 3 = 13
                13 + 4 + 5 = 22
                22 + 5 + 7 = 34
                34 + 6 + 11 = 51
                51 + 7 + 13 = 71
                71 + 8 + 17 = 96
                96 + 9 + 19 = 124
                124 + 10 + 23 = 157
                First is numbers (1, 2, 3, 4...) etc and second is prime numbers (1, 2, 3, 5, 7, 11, 13...).

3.    3;    The series is:
                664 + 4 ÷ 2 = 334
                334 + 8 ÷ 4 = 85.5
                85.5 + 12 ÷ 6 = 16.25
                16.25 + 16 ÷ 8 = 4.03125
                4.03125 + 20 ÷ 10 = 2.403125

4.    5;    The series is:
                13 × 2 + 7 = 300
                33 × 3 + 11 = 110
                110 × 4 + 13 = 453
                453 × 5 + 17 = 2282
                2282 × 6 + 19 = 13711
                13711 × 7 + 23 = 96000
                All are prime number > 7.

5.    3;    The series is:
                0.8 × 1 + 3 = 3.8
                3.8 × 2 + 5 = 12.6
                12.6 × 3 + 7 = 44.8
                44.8 × 4 + 9 = 188.2
                188.2 × 5 + 11 = 952

 6. 2; x ³ y

I.  20 x2 – 31 x + 12 = 0
5x (4x-3) – 4 (4x – 3) = 0
                   (4x –3) (5 x – 4) = 0
                   x = 3/4, 4/5
             II. 20 y2 –  y – 12 = 0
                   (5 y – 4 ) (4y + 3) = 0
                      y = 4/5, - 3/4      
           Ans is 2 X > Y


7. 1; X > y
 I.               3x2 – 47 x + 184 = 0
                   (x– 8) (3x – 23) = 0
                   x = 8, 23/3
                   II. 2 y2 – 23 y + 66 = 0
                   (y –6) (2 y –11) = 0
            y = 6,   11/2


8. 2;
I. 30 x – 25  x – 24  x + 20
                   (5√x– 4) (6√x– 5) = 0
                     x = 16/25, x = 25/36
   
                   II.  42 y – 5√y– 25 = 0
                   (6 √y– 5) (7√y + 5) = 0

                   y = 25/36, y = 25/49
                   Ans is 2 X > Y


9. 5; no relation can be established
I. x2 – 10√3+ 63 = 0
                   x2 – 10√3+ 63 = 0
                   ( x – 3√3 ) (x –7√3)= 0
                   x = 3√3, 7√3

                   II. y2 – √2y – 24 = 0
                    (y – 4√2) (y + 3√2) = 0

                   y = 4√2, -3√2

               
10. 2; x ³ y

 I. x2 – 14 x – 48 = 0
                   (x – 6 ) (x – 8) = 0
                   x = 6, 8

                   II. y2 – y – 30 = 0
                   (y  + 5) (y - 6) = 0

                   y = -5 , 6


Quantitative Aptitude Quiz - Data Interpretation

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Direction (1-5) : Production of two categories of  chemicals by factory A is given, Answer the question based on given data.



1.  The ratio of the number of organic chemicals for which the production has fallen to the number of inorganic chemicals for which production has fallen is :
(1)  6 : 5                                      
(2)  3 : 2                            
(3)  2 : 3                                            
(4)  1 :1                                      
(5) None of these

2.    Of all the chemicals shown, the highest percentage increase in production has been exhibited for :
(a) Fatty acids                        
(b) Ethylene glycol      
(3) Aniline        
(4) Sodium bicarbonate      
(5) None of these

3. The difference between production sum of production of ethylene glycol, pthalic anhydride and phenol in 2002-03 and Calcium carbide, sodium bicarbonate and Aluminium chloride in 2003-04 is
(1) 336527                          
(2) 335667                          
(3) 326547                                              
(4) 345887                                          
(5) None of these

4. The percentage change in total production of chemicals between the two years is closest to :
(1) 5.4%
(2) 6.9%
(3) 7.2%
(4) 4.5%
(5) None of these

5. Which among the following has least change in production as compared to previous year :
(1) Bleaching powder    
(2) Aluminium chloride  
(3) Calcium carbonate
(4) Calcium carbide        
(5) None of these


Direction(6-10) : State wise Literacy and Population growth:



6.       Which of the following states shows a higher Percentage increase in female literacy than the percentage increase in total literacy?
(i) Maharashtra                    
(ii) Himachal Pradesh              
(iii) Kerala
(iv) Karnataka
(1). (i) Only                            
(2).  (i),(ii)&(iv)          
(3).  (i) and (iii)
(4). All of the above            
(5).  None of the above

7.       For the state showing the minimum percentage increase in total literacy, the numerical ratio of the percentage    increase in total literacy to the change in percentage population growth rate is nearly (take absolute values only)
(1). 508.5                  
(2). 558.5                          
(3). 598.5
(4). 578.5                  
(5) .None of these

8.       How many states has more increase in female literacy as compared to the average of percentage increase in female literacy in all the years together:
        (1) 5                            
        (2) 3                    
        (3) 7
 (4) 4                            
 (5) 6  

9.       The ratio of the overall simple average of the percentage increase in female literacy to the simple average percentage increase in female literacy of those states where the percentage increase is more than the overall average is:
(1) 0.972                  
(2) 0.818          
(3) 0.89
(4) 0.146                  
(5) None of these

10.       The ratio of the simple overall average of the percentage increase in female literacy to the simple overall average of the percentage increase in total literacy is approx equal to :
(1) 0.894                  
(2) 0.968          
(3) 1.033
        (4) 0.788                          
        (5) None of these



ANSWERS


1.        (3)  4:6=2:3
2.        (2)  Ethylene glycol,     454371-327387=126984,   (126984/327387)×100=38.78%
3.        (1)
4.        (2)  2910353(2003-04)-2728101(2002-03)=182252,    182252/2728101=6.9%
5.        (4)  Calcium Carbide, 83445-83388=57
6.      (3) ; Maharashtra and Kerala
7.      (2) ; Bihar, 22.34/0.04=558.5
8.      (1) ;
9.      (c) ; 26.496/29.436=0.89 approx
10.  (b); 26.496(average of increase in female literacy average)/27.372(average of increase in total literacy)=0.968

Quantitative Aptitude Quiz - X

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Directions (Q. 1 - 5): Each question below is followed by two statements I and II. You are to determine whether the data given in the statement is sufficient to answer the question. You should use the data and your knowledge of Mathematics to choose among the possible answers.

Give answer—

1)  If the statement I alone is sufficient to answer the question, but the statement II alone is not sufficient.
2)  If the statement II alone is sufficient to answer the question, but the statement I alone is not sufficient.
3)  If both statements I and II together are needed to answer the question.
4)  If either the statement I alone or the statement II alone is sufficient to answer the question.
5)  If you cannot get the answer from the statements I and II together, but need even more data.


1. A man covers a distance by car. How many kilometer does he cover?
I. Had he moved 10 kmph faster, he would have taken one hour less.
II.    Had he moved 8 kmph slower, he would have taken one hour more.

2.√ ((x – y)/x)
I.  x/y = 4/3        
II.    y = 3

3. Find the three consecutive positive integer.
I.     If their product is 120.
II.    If their sum is 15?

4. What is the area of a equilateral triangle?
I.     Height of the triangle is 8 m.
II.    Co-ordinates of two vertices are (3, 3) & (7, 5).

5. Two trains are moving on parallel tracks in opposite direction. In how many seconds will the trains cross each other completely?
I. Ratio of their speeds is 3 : 4.
II. First train crosses a pole in 5 seconds and second train crosses the pole in 6 seconds.      

Directions (Q. 6- 10): Following line graph shows percentage profit of two companies A and B over the years 2000-2005. Answer the given questions based on this graph?



6. If in year 2002, the expenditure of Company B was Rs 45 lakhs, then what is the income of Company B in the same year?
1) 50 lakhs
2) 52 lakhs
3) 54 lakhs
4) 55 lakhs
5) 60 lakhs

7. For how many years the difference of the net profit for two companies was the maximum?
1) 1
2) 2
3) 3
4) Data inadequate
5) None of these

8. If, for Company A, the expenditure in year 2000 and 2002 was 1.2 crores together, then what is the total income in these years?
1) 1.86 crores
2) 1.8 crores
3) 1.92 crores
4) Data inadequate
5) None of these

9. In how many years, the total income is less than double the total expenditure in that year for Company B?
1) 1
2) 2
3) 3
4) 4
5) 5

10. If the income of Company A in 2000 and Company B in 2004 is same Rs 42 lakhs, then what is the total expenditure of Company A in 2000 and Company B in 2004?
1) 52 lakhs
2) 64 lakhs
3) 56 lakhs
4) 60 lakhs
5) None of these


ANSWERS

 1. 3;
Let the distance be D km. Time is T hours. Speed = S km/hr.
Using Statement I:
D = S × T = (S + 10) (T – 1) Þ S = 10T – 10
Using Statement II:
D = S × T = (S – 8) (T + 1) Þ S = 8T + 8
Using Both:
10T – 10 = 8T + 8 Þ T = 9 Hours, S = 80 km/hr
D = 9 × 80 = 720 Km
So the Answer is (3) ie., using both statements together.

2. 1
√((x - t)/ x) = √(1 – (y/x))

3. 4;
From statement I alone we can find a unique solution as it is given that three integers are consecutive and positive with product 120. So the unique integers will be 4, 5, 6.
From statement II alone we can find a unique solution.
Let the positive integers be a, a + 1, a + 2.
So, a + a + 1 + a + 2 = 15
a = 4 and the integers are 4, 5, and 6.

4.    4;    Using Statement I:
                We know height of equilateral triangle is  .
                Here height is given so we can find the side and hence the area of triangle.
                Using Statement II:
                As the co-ordinates of two vertices are given we can find the length of the side of the triangle and hence the area of the equilalteral triangle.

5.    3;    Let the length of trains be L1 and L2.
                Using Statement I:
                We can only find their speeds as 3x and 4x.
                Using Statement II:
                We can find L1 = 5 × Speed of Trains,
                                       L2 = 6 × Speed of second Trains
                Using Both:
                L1 = 5 × 3x
                L2 = 6 × 4x
                Required time to cross each other completely is
                  (L1 + L2)/ (3x + 4x) = (15x + 24x)/ 7x = 39/7
                  Hence, the answer is (3).



6.    3;    Profit =   (Profit % * Expenditure)/100 =  (20*45)/100 = 9
                 Income = 45 + 9 = 54 lakhs

7.    4;    Data is not sufficient.

8.    4;    Data inadequate.

9.   5;   (Income - Expenditure)/ Exp*100= P%
             Expenditure is 100% in each year and Income%  = Exp% + Profit%

10.    1;    Profit of A in 2000 = (42*50)/150 = 14 lakhs
                Expenditure = Income – Profit = 42  – 14 = 28 lakhs
                Profit of B in 2004 =  (42*75)/175 = 18 lakhs
                  Expenditure = 42 – 18 = 24 lakhs
                 Total expenditure = 28 + 24 = 52 lakhs

Quantitative Aptitude Quiz - IX

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Welcome to ourindiajobs.com online test on Quantitative AptitudeQuantitative tests will helps you to crack your online bank exams. This material on Quantitative will be covered with all topics. Little bit of concentration and hard work may do this online test on Quantitative. Practice more tests on Quantitative it will helps you to manage time. Success comes from confidence. Go ahead with confidence, win the race and achieve your target. All the best for test.

1. √2900 × √498 ÷ √251 = ? ÷ 8
(1) 600
(2) 670
(3) 770
(4) 750
(5) 730


2. 89.998% of 598.9 + 51.002% of 899.99 – 171.015 = ?
(1) 990
(2) 830
(3) 910
(4) 870
(5) 980

3. (341/20.002) ÷ (511/30.07) × (179.909/49.919) = ?
(1) 36
(2) 7.2
(3) 72
(4) 3.6
(5) 1.8

4. 8999 ÷ 90.005 × 95.998 = ? × 20.999
(1) 420
(2) 320
(3) 540
(4) 525
(5) 457

5. (39.99)2 – (9.9)2 – (15.1)2 = ?
(1) 1375
(2) 1275
(3) 1100
(4) 1175
(5) 725

Directions (6 – 10): What will come in place of the question-mark (?) in the following questions?

6. (13/18) of  24% of 1023 = 120 + ?
(1) 60    
(2) 57
(3) 87
(4) 120
(5) None of these

7. 5322– 8241 + 3642 + 3120 = ? + 1203
(1) 2640
(2) 2569
(3) 1639
(4)  2549
(5) None of these

8. 53 × 25 ÷  √625 – 32 =? – 42
(1) 132
(2) 157
(3) 155
(4) 133
(5)  None of these

9. √(58 × 10 + 120 + 29) = (?)2
(1) 27
(2) √27
(3) 272  
(4) 729
(5) 725

10. 62 × 362 = 6? × 216
(1) 4
(2) 3  
(3) 6
(4) 2
(5) None of these

Directions (11–15): What will come in the place of the question mark (?) in the following number series?

11. 13    16    14     17     15     18    (?)
(1) 16  
(2) 15    
(3) 14
(4) 21
(5) None of these

12. 25    50    35    70    55    110    95    (?)
(1) 196  
(2) 80
(3) 185
(4) 190
(5) None of these

13. 10     14     26    50    90     (?)
(1) 100  
(2) 125
(3) 150
(4) 155
(5) None of these

14. 2      8   20    44    92   (?)
(1)189  
(2)188
(3) 288
(4) 818
(5) None of these

15. 15      21     33     51    75    (?)
(1) 103
(2) 102
(3) 105
(4) 95
(5) None of these



ANSWERS

1. (1)
Explanations -
? =√2290×√498÷√251×8
≈ 54×22÷16×8
≈600
             

2. (2)
Explanations -
? = 89.998% of 598.9+51.002% of 899.99 - 171.015
≈90% of 600 + 51% of 900 – 171.05
        ≈540+459 – 171

        ≈830

3. (4)
Explanations -
? = (341/20.002) ÷ (511/30.07) * (179.909/49.919) = ?
     ≈ 340/20 * 30/510 * 180/50

     ≈ 3.6

4. (5)
Explanations -
? = 8999÷90.005×95.998÷20.999
         ≈9000÷90×96÷21
         ≈9600÷21
         ≈457


5. (2)
Explanations -
? = 39.992 – 9.92 – 14.92
≈ 402 – 102 – 152
≈ 1275

6. (2)
Explanations -
? = (13/18) of 24% of 1203 – 120
= (13/18)*(24/100)*1203-120
= ((13*4*341)/100) – 120
= 177.32 – 120
= 57 (approx)

7. (5)
Explanations -
? = 5322 – 8241 + 3642 +3120 – 1023 = 2820
? = 53 * 25 ÷ √625 – 32 + 42
= 125 * 25 ÷ 25 – 9 + 16
= 125 + 7
= 132

8. (1)
Explanations -
(1) ? = 53 * 25 ÷ √625 – 32 + 42
= 53 * 25 ÷ 25 – 9+16
= 125 + 7
= 132

9. (2)
Explanations -
(?)2 = √(58 * 10 + +29)
√729 = 27
? = √27

10. (2)
Explanations -
6? = (62 × 362)/ 216
6? = (62 × 64)/63  
6? = 63
? = 3

11. (1)
Explanations -
13,        16,        14,        17,        15,         18,         (16)
              +3           -2         +3         -2          +3          -2

12. (4)
Explanations -
25,     50,    35,    70,    55,   110,  95,    (190)
      ×2     -15     ×2    -15    ×2       -15    ×2

13. (3)
Explanations -
10,     14,      26,                    50,      90,        (150)
+4      +12     +24    +40      +60

     +8        +12    +16      +20

14. (2)
Explanations -
2        8         20       44       92        (188)
    +6     +12     +24     +48      +96

15. (3)
Explanations -
(3) 15      21       33      51       75        (105)

   +6       +12    +18    +24      +30

Quantitative Aptitude Quiz - VIII

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Directions (1–5): Study the given information carefully and answer the questions that follow—

An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles.

1. If two marbles are picked at random, what is the probability that both are red?
(1) 1/3
(2) 1/7
(3) 3/5
(4) 2/3
(5) None of these


2. If three marbles are picked at random, what is the probability that two are blue and one is yellow?
(1) 10/455
(2) 35/355
(3) 18/455
(4) 18/35
(5) None of these

3. If four marbles are picked at random, what is the probability that at least one is blue?
(1) 2/5
(2) 60/65
(3) 44/455
(4) 22/21q
(5) None of these

4. If two marbles are picked at random, what is the probability that either both are green or both are yellow?
(1) 3/5
(2) 2/25
(3) 14/25
(4) 4/105
(5) None of these

5. If four marbles are picked at random, what is the probability that one is green, two are blue and one is red?
(1) 24/455
(2) 14/455
(3) 13/55
(4) 134/165
(5) None of these

Directions (6–10): Study the following graph carefully and answer the questions that follow:
Number of candidates Appeared in the examination and percentage of students passed from various colleges

Table is given at the end.

6. What is the ratio between the number of students passed from institute U in 2007 and the number of students passed from institute Q in 2005 respectively?
(1)  95: 154
(2) 154: 95
(3) 36: 77
(4) 77: 36
(5) None of these

7. What is the ratio between the average number of students appeared from institute P for all the years and that from institute S respectively?
(1) 463: 353
(2) 353: 463
(3) 461: 333
(4) 333 : 461
(5) None of these

8. What is the total number of students passed from all institutes together in year 2010?
(1) 3790
(2) 3970
(3) 2590
(4) 2930
(5) None of these

9. What is the overall percentage of students passed from all institutes together in 2008? (rounded off to nearest integer)
(1) 68
(2) 70
(3) 69
(4) 71
(5) None of these

10. Approximately, what is the overall percentage of students passed from institute R for all the years?
(1) 60
(2) 70
(3) 75
(4) 55
(5) 65


ear
Colleges
P
Q
R
S
T
U
App
%pass
App
%pass
App
%pass
App
%pass
App
%pass
App
%pass
2005
900
60
1080
40
600
65
1280
50
1200
45
1360
60
2006
1040
50
860
70
700
60
1240
40
1160
70
1120
70
2007
860
60
980
70
760
50
1160
50
1360
70
1400
66
2008
800
65
1200
75
900
70
1200
75
1440
60
1560
70
2009
960
50
1140
50
800
75
1400
65
1400
48
1120
50
2010
1100
40
900
60
1000
68
1500
60
900
50
1300
60
2011
1000
58
940
60
940
60
1440
70
1120
60
1440
50



ANSWERS


1. (2) Required probability = 6C2/15C2 = 1/7

2. (3)  (4C2 * 3C1)/15C3 = 18/455

3. (5) Required Probability = 1 – Probability that none of the
          Four marbles is blue =  1 - 11C4/15C4 = 69/91

4. (4) Required probability =  (2C2 + 3C2)/15C2 = 4/105

5. (1) Required Probability =  (2C1 * 4C2 * 6C1)/ 15C4 = 24/455

6. (4) Number of students passed from institute U in 2007 = 66% of 1400 = 924
Number of students passed from institute Q in 2005 = 40% of 1080 = 432
Required ratio = 924: 432 = 77: 36

7. (4) Average number of students appeared from institute P for all the years = 6660/7
Average number of students appeared from institute S for all the years = 9220/7
Required ratio = 6660: 9220 = 333: 461

8. (1) Required sum = 40% of 1100 + 60% of 900 + 68% of
       1000 + 60% of 1500 + 50% of 900 + 60% of 1300
      = 440 + 540 + 680 + 900 + 450 + 780 = 3790

9. (3) Total number of students appeared in 2008 = 800 +
                1200 + 900 + 1200 + 1440 + 1560 =7100
                Total Number of students passed in 2008 = 520 +
                 900 + 630 + 900 + 864 + 1092 = 4906
                   Required percentage =  4906/7100 * 100 = 69.06

10. (5) Total number of students appeared from institute R
                  = 5700
Total Number of students Passed from institute R = 3664
Required percentage =  3664/5700 * 100 = 65approx