Quantitative Aptitude Quiz - XII
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Directions (Q. 1-5): What should come in place of question mark (?) in the following number series?
1. 5, 41, 321, 1921, 7681, 15361, ?
1) 21381
2) 23710
3) 22173
4) 23121
5) 1
2. 1, 3, 7, 13, 22, 34, 51, 71, 96, 124, ?
1) 137
2) 147
3) 157
4) 167
5) None of these
3. 664, 334, 85.5, 16.25, 4.03125, ?
1) 2.73012
2) 3.17203
3) 2.403125
4) 3.220175
5) None of these
4. 33, 110, 453, 2282, 13711, ?
1) 95673
2) 96747
3) 96312
4) 951321
5) 96000
5. 0.8, 3.8, 12.6, 44.8, 188.2, ?
1) 758.6
2) 868.8
3) 952.00
4) 1012.2
5) 1112.2
Directions (Q. 6-10): In the following questions two equation numbered I and II are given. You have solve the equation and give answer if-
1. x > y
2. x > y
3. x < y
4. x < y
5. x = y or the relationship cannot be established.
6.
I. 20x2 - 31x + 12 = 0
II. 20y2 - y - 12 = 0
7.
I. 3x2 - 47x + 184 = 0
II. 2y2 - 23y + 66 = 0
8.
I. 30x - 49√x + 20 = 0
II. 42y - 5√y - 25 = 0
9.
I. x2 - 10√3x + 63 = 0
II. y2 - √2y - 24 = 0
10.
I. x2 - 14x + 48 = 0
II. y2 - y - 30 = 0
ANSWERS:
1. 5; The series is:
5 × 10 – 9 = 41
41 × 8 – 7 = 321
321 × 6 – 5 = 1921
1921 × 4 – 3 = 7680
7681 × 2 – 1 = 15361
15361 × 0 – (–1) = 1
2. 3; The series is:
1 + 1 + 1 = 3
3 + 2 + 2 = 7
7 + 3 + 3 = 13
13 + 4 + 5 = 22
22 + 5 + 7 = 34
34 + 6 + 11 = 51
51 + 7 + 13 = 71
71 + 8 + 17 = 96
96 + 9 + 19 = 124
124 + 10 + 23 = 157
First is numbers (1, 2, 3, 4...) etc and second is prime numbers (1, 2, 3, 5, 7, 11, 13...).
3. 3; The series is:
664 + 4 ÷ 2 = 334
334 + 8 ÷ 4 = 85.5
85.5 + 12 ÷ 6 = 16.25
16.25 + 16 ÷ 8 = 4.03125
4.03125 + 20 ÷ 10 = 2.403125
4. 5; The series is:
13 × 2 + 7 = 300
33 × 3 + 11 = 110
110 × 4 + 13 = 453
453 × 5 + 17 = 2282
2282 × 6 + 19 = 13711
13711 × 7 + 23 = 96000
All are prime number > 7.
5. 3; The series is:
0.8 × 1 + 3 = 3.8
3.8 × 2 + 5 = 12.6
12.6 × 3 + 7 = 44.8
44.8 × 4 + 9 = 188.2
188.2 × 5 + 11 = 952
6. 2; x ³ y
I. 20 x2 – 31 x + 12 = 0
5x (4x-3) – 4 (4x – 3) = 0
(4x –3) (5 x – 4) = 0
x = 3/4, 4/5
II. 20 y2 – y – 12 = 0
(5 y – 4 ) (4y + 3) = 0
y = 4/5, - 3/4
Ans is 2 X > Y
7. 1; X > y
I. 3x2 – 47 x + 184 = 0
(x– 8) (3x – 23) = 0
x = 8, 23/3
II. 2 y2 – 23 y + 66 = 0
(y –6) (2 y –11) = 0
y = 6, 11/2
8. 2;
I. 30 x – 25 x – 24 x + 20
(5√x– 4) (6√x– 5) = 0
x = 16/25, x = 25/36
II. 42 y – 5√y– 25 = 0
(6 √y– 5) (7√y + 5) = 0
y = 25/36, y = 25/49
Ans is 2 X > Y
9. 5; no relation can be established
I. x2 – 10√3+ 63 = 0
x2 – 10√3+ 63 = 0
( x – 3√3 ) (x –7√3)= 0
x = 3√3, 7√3
II. y2 – √2y – 24 = 0
(y – 4√2) (y + 3√2) = 0
y = 4√2, -3√2
10. 2; x ³ y
I. x2 – 14 x – 48 = 0
(x – 6 ) (x – 8) = 0
x = 6, 8
II. y2 – y – 30 = 0
(y + 5) (y - 6) = 0
y = -5 , 6
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